I have 2 pet pairs that I need help with. Can you correct me if I'm wrong please.

 

Skyblue cock to Dark green opaline spangle hen.

 

I will get 50% spangles and 50% normals.

The cocks will be split opaline

50% dark greens and 50% light greens, how many of these will be split to blue?

 

Next pair is:

Opaline yellowface type 1 skyblue hen paired to dark green cock.

 

I will get 50% yellowface normals and 50% normals.

Cocks will be split opaline

Colours will be light and dark green, how many of these will be split to blue?

 

Thanks.

I have 2 pet pairs that I need help with. Can you correct me if I'm wrong please.

 

Skyblue cock to Dark green opaline spangle hen.

 

I will get 50% spangles and 50% normals.

The cocks will be split opaline

50% dark greens and 50% light greens, how many of these will be split to blue?

All greens will be split to blue

Next pair is:

Opaline yellowface type 1 skyblue hen paired to dark green cock.

 

I will get 50% yellowface normals and 50% normals.

Cocks will be split opaline

Colours will be light and dark green, how many of these will be split to blue?

All greens will be split to blue

 

When you do the charting for the blue this is how it works

 

b = blue

G = Green (dominant)

each bird gets 2 genes from each parent

 

b b

G Gb Gb

b bb bb

 

Gb = Green split to blue

bb = blue

Edited January 31, 200916 yr by Elly

The answer to your question, how many will be split to blue...if the green bird of the pair isn't split, then all of them will be green, split to blue.

Edited January 31, 200916 yr by Jen144

The answer to your question, how many will be split to blue...if the green bird of the pair isn't split, then all of them will be green, split to blue.

 

That is correct, I based mine on the assumation that the Greens were split to blue. :rofl:.

Thanks very much Elly and Jen144. So I was correct?

 

Elly- the chart you posted is that just for my pairs? or does it work for any pair?

 

I do not understand it.

 

 

 

b = blue

G = Green (dominant)

each bird gets 2 genes from each parent

 

b b (why are these 2 blue genes here? Are they the parent? )

 

G Gb Gb (is this the green parent? If it is then why is their blue here aswell?)

b bb bb (Im assuming this is the blue parent)

 

Gb = Green split to blue

bb = blue

Edited January 31, 200916 yr by Pearce

Elly- the chart you posted is that just for my pairs? or does it work for any pair?

It will work with any pair that is Green split to blue x Blue

 

b = blue

G = Green (dominant)

each bird gets 2 genes from each parent

 

b b (why are these 2 blue genes here? Are they the parent? ) the blue bird has 2 blue genes, the only way the blue can be visual is the bird carries 2 blue genes, if it had a green gene then it would be Green Split to Blue.

G Gb Gb (is this the green parent? If it is then why is their blue here aswell?) The green bird has 2 genes they will be either 2 Greens (GG) or 1 Green and split to blue which is 1 gene (Gb), so if your Green is split to blue I was showing the chart to show how you can do the %'s, so the Green Bird will give 1 gene either it will be Green or Blue and the Blue bird can ONLY give a blue gene because that is all it has 2 blue genes.

b bb bb (Im assuming this is the blue parent) bb is the blue off spring, the 2 b's on the top represent the blue parent's genes

Gb = Green split to blue

bb = blue

Thanks very much Elly.

 

Could this table I just made now do the same thing as yours?

 

Gb (Green hen split to blue) paired to bb (blue cock)

 

Each parent gives the chick 2 genes right?

 

So: GGBB GGBB (all the chicks would be green split blue?)

 

 

 

 

Where as if it were: Gb (green cock split to blue) Gb (green hen split to blue)

How would this work?

I know you can get blues from a pairing like this. How would 2 blue genes from each parent be passed on without green genes being passed?

 

I understand if you dont want to explain it, I am so confused.

Edited January 31, 200916 yr by Pearce

Each bird has 2 color genes either 2 Greens - GG OR 1 Green and 1 Blue (GB)

Your chart would be wrong because you gave each bird 4 color genes GGBB

 

So if you have example:

 

GG (1 Green Hen Bird with 2 Green Genes) x bb (1 blue Cock bird with 2 Blue Genes) you would chart it out and split apart the genes.

 

1 cock blue gene 1 cock blue gene

 

1 hen Green Gene G (hen) B (cock) G (hen) b (cock)

 

1 hen Green Gene G(hen) B (cock) G (hen) b (cock)

 

then what you do is go diagonial to figure out the charting like when you do multiplication (that is the best way I can explain it because I don't have arrows)

 

Now you figure out this one

 

Gb (green split to blue which is a green bird with 1 green gene and 1 blue gene) x bb (blue bird with 2 blue genes)

Now you figure out this one

 

Gb (green split to blue which is a green bird with 1 green gene and 1 blue gene) x bb (blue bird with 2 blue genes)

 

Gb x bb

 

1 cock green gene(g) 1 cock blue gene(:rofl: x 1 hen blue gene (:rofl: 1 hen blue gene (:rofl:

 

GB BB

 

Thats as far as I can get, I dont know what to do after this. Do you repeat the same thing again?

Here is a picture of what I did.

 

 

Somehow I think I am incorrect.

Your 1/2 way there, I wish I knew how to do the drawing stuff

 

make the chart the way I did, it makes it easier to see it

 

B B

 

G Baby 1 (GB) Baby 2 (GB)

 

 

B Baby 3 (BB) Baby 4 (BB)

Edited January 31, 200916 yr by Elly

I think I may understand it now.

 

A male green bird split to blue x A female green bird split to blue

 

GB GB

 

The chick takes one gene from each parent right?

 

The first chick takes the green from the cock and the green from the hen - resulting in a green with no split

The second chick takes the blue from the cock and the green from the hen - resulting in a green split to blue

The third chick takes the green from the hen and the blue from the cock - resulting in a green split to blue

The fourth chick takes the blue from the cock and the blue from the hen - resulting in a blue bird.

yep you got it and you use this method with any non-sex linked gene example spangle, recessive pied, dominant pied...

okay thanks very much Elly.

 

Is this correct.

 

Male green bird split to blue x to a green hen

GB x GG

 

First chick takes the green from the cock and the green from the hen - GG

Second chick takes the blue from the cock and the green from the hen - Gb

Third chick takes the green from the cock and the green from the hen - GG

Fourth chick takes the blue from the cock and the green from the hen - Gb

 

When the chicks come out are they in this order or is it random?

okay thanks very much Elly.

 

Is this correct.

 

Male green bird split to blue x to a green hen

GB x GG

 

First chick takes the green from the cock and the green from the hen - GG

Second chick takes the blue from the cock and the green from the hen - Gb

Third chick takes the green from the cock and the green from the hen - GG

Fourth chick takes the blue from the cock and the green from the hen - Gb

 

When the chicks come out are they in this order or is it random?

 

A green male split to blue mated with a green female will get a percentage of greens, and greens split to blue. (50/50,approximately, I think) And no they don't come in that order though. It is random, and you don't necessarily get 50% greens and 50% greens split for blue each clutch. That's just an average, over a few clutches.

Jen is right that is a simple % you may get all green or you might get all blue but it gives you an idea of what your outcome out so for example when you look at that chart you have a even chance of getting greens either not split or split like but they are just %. A great example is my husband and I we both have brown eyes and both split for blue eyes because amazing both our kids have blue eyes that is a 25% chance of that but we acheived it :rofl:

okay Thanks very much all.