Good point Dave, it is a percentage so basically if that pair had a 100% chicks that it the rough percentage you should get. A good way to figure out what you'll get is say which one you would prefer and then remove it from the equation :thumbs_up:

Thankyou very much Dave Jimmy and Jaz.What about these:Skyblue with dark green: dd + dD =?Dark green with mauve: dD + DD =?Light green with olive: dd + DD = ?

Thankyou very much JaznjiI am going to study this as hard as I can.Thanks very much again.Edit:I think I may understand it, please look at these examples and tell me if im right.Skyblue paired to skyblue:dd + dd = dd dd dd dd dd dd dd (Always be no dark factor?)Dark green paired to dark green:dD + dD = dd dD dD DD (what happens after the double factor? what if their are more than 4 chicks? does it repeat itself?)Mauve to mauve:Im assuming its: DD + DD = DD DD DD DDAm I correct?

Yes Pearce, you are right on target. Your Dark green to Dark green should give you one light green, two dark greens and an olive. Dave and Jim are correct too - it is a theoretical ratio and if you bred 100 chicks the numbers would work out pretty close to that 1:2:1 ratio but individual nests will show variability. Mauve to mauve will always give you mauve. Another example for you to study on: a light green to a dark green is dd x dD = dd, dd, dD and dD (half light greens and half dark greens). Once you have got this method in your head you'll never have to work it out on paper again.

Thankyou very much Dave Jimmy and Jaz.What about these:Skyblue with dark green: dd + dD =?Dark green with mauve: dD + DD =?Light green with olive: dd + DD = ?

To answer your questions: Skyblue x dark green (dd x dD) If the dark green is double factor green you will get half light green and half dark green birds but they will be carrying blue as a recessive. If the dark green is already split blue you will get half birds with no dark factors (skyblues or light greens split for blue) and half birds with one dark factor (cobalts or dark greens split for blue). Dark green with mauve: (dD x DD) If the dark green is double factor green you will get half dark greens and half olives and they will be carrying blue as a recessive. If the Dark green is split for blue you will get half the birds with one dark factor (cobalts or dark greens split for blue) and half birds with two dark factors (mauves or olives split for blue). Light green to olive will give you all birds with one dark factor, that is all dark greens.The equivalent in blue series is skyblue to mauve which will give you all cobalts.

okay i understand that to. Im just guessing but would light green + mauve =

dd + DD = dD dD dD dD (All dark green babies?)

Thankyou very much JaznjiI am going to study this as hard as I can.Thanks very much again.Edit:I think I may understand it, please look at these examples and tell me if im right.Skyblue paired to skyblue:dd + dd = dd dd dd dd dd dd dd (Always be no dark factor?)Dark green paired to dark green:dD + dD = dd dD dD DD (what happens after the double factor? what if their are more than 4 chicks? does it repeat itself?)Mauve to mauve:Im assuming its: DD + DD = DD DD DD DDAm I correct?

Yes Pearce, you are right on target. Your Dark green to Dark green should give you one light green, two dark greens and an olive. Dave and Jim are correct too - it is a theoretical ratio and if you bred 100 chicks the numbers would work out pretty close to that 1:2:1 ratio but individual nests will show variability. Mauve to mauve will always give you mauve. Another example for you to study on: a light green to a dark green is dd x dD = dd, dd, dD and dD (half light greens and half dark greens). Once you have got this method in your head you'll never have to work it out on paper again.

Thankyou very much Dave Jimmy and Jaz.What about these:Skyblue with dark green: dd + dD =?Dark green with mauve: dD + DD =?Light green with olive: dd + DD = ?

To answer your questions: Skyblue x dark green (dd x dD) If the dark green is double factor green you will get half light green and half dark green birds but they will be carrying blue as a recessive. If the dark green is already split blue you will get half birds with no dark factors (skyblues or light greens split for blue) and half birds with one dark factor (cobalts or dark greens split for blue). Dark green with mauve: (dD x DD) If the dark green is double factor green you will get half dark greens and half olives and they will be carrying blue as a recessive. If the Dark green is split for blue you will get half the birds with one dark factor (cobalts or dark greens split for blue) and half birds with two dark factors (mauves or olives split for blue). Light green to olive will give you all birds with one dark factor, that is all dark greens.The equivalent in blue series is skyblue to mauve which will give you all cobalts.

I wish I could figure out how to send these posts with breaks between paragraphs. I try to set it out so it can be easily understood but something happens in posting and it all gets mushed together.

okay i understand that to. Im just guessing but would light green + mauve =dd + DD = dD dD dD dD (All dark green babies?)

You anticipated me! Our posts crossed. Yes, I think you have the trick.

Lost power and I had so much typed :glare:

Recap:

 

Key:

dd = 0 dark factor

dD = 1 dark factor

DD = 2 dark factor

 

0 dark factor + 0 dark factor = dd dd dd dd dd dd

1 dark factor + 1 dark factor = dd dD dD DD

2 dark factor + 2 dark factor = DD DD DD DD DD

 

0 dark factor + 1 dark factor = dd dd dD dD (50% each)

0 dark factor + 2 dark factor = dD dD dD dD

 

1 dark factor + 2 dark factor = dD dD DD DD (50% each)

 

Is this all right? If so I can copy it into wordpad

 

Thanks so much all

Edited January 1, 200916 yr by pearce

Here in our FAQ Mutation Section you will see the Green & Blue Dark Factor Explanation to check back on :glare:

http://forums.budgiebreeders.asn.au/faqs/i...t=6&seite=1

Lost power and I had so much typed :glare:

Recap:

 

Key:

dd = 0 dark factor

dD = 1 dark factor

DD = 2 dark factor

 

0 dark factor + 0 dark factor = dd dd dd dd dd dd

1 dark factor + 1 dark factor = dd dD dD DD

2 dark factor + 2 dark factor = DD DD DD DD DD

 

0 dark factor + 1 dark factor = dd dd dD dD (50% each)

0 dark factor + 2 dark factor = dD dD dD dD

 

1 dark factor + 2 dark factor = dD dD DD DD (50% each)

 

Is this all right? If so I can copy it into wordpad

 

Thanks so much all

 

Well done, looks perfect. Jaz (Also see Elly's post)

Hi

 

Just wondering if their are equasions like these for other mutation parings? Example: Dominant pied to normal, spangle to dilute etc.. Any equasions you have could you please share them.

 

Thanks very much

 

Edit:

Ive just found a table in the faq and Im wondering if I am right in understanding it.

 

For a spangle to spangle paring, Would this table be correct:

Single Factor X Single Factor

= 25% Double Factor

= 50% Single Factor

= 25% Normal

 

 

For spangle to a normal pairing, would this table be correct:

Single Factor X Normal

= 50% Single Factor

= 50% Normal

 

For rec pied to rec pied, would this table be correct:

Recessive X Recessive

= 100% Recessive

 

for light green split blue to light green split blue, would this table be correct?

Normal/Recessive X Normal/Recessive

= 25% Normal

= 50% Normal/Recessive

= 25% Recessive

NB: Visually you will be unable to tell which

normals are also split recessive

 

if these are correct then I am well on my way to mastering genetics.

Edited January 3, 200916 yr by pearce

Yes :hug:

HiJust wondering if their are equasions like these for other mutation parings? Example: Dominant pied to normal, spangle to dilute etc.. Any equasions you have could you please share them.Thanks very muchEdit:Ive just found a table in the faq and Im wondering if I am right in understanding it.For a spangle to spangle paring, Would this table be correct:Single Factor X Single Factor = 25% Double Factor= 50% Single Factor= 25% NormalFor spangle to a normal pairing, would this table be correct:Single Factor X Normal = 50% Single Factor= 50% NormalFor rec pied to rec pied, would this table be correct:Recessive X Recessive = 100% Recessivefor light green split blue to light green split blue, would this table be correct?Normal/Recessive X Normal/Recessive = 25% Normal= 50% Normal/Recessive= 25% RecessiveNB: Visually you will be unable to tell which normals are also split recessiveif these are correct then I am well on my way to mastering genetics.

Yes! Note that the dominant/recessive thing happening with the greens and blues works in the same way. Light green/blue x light green/blue = 25% light green 50% light green split blue and 25% blue.Out of your pairing above it will be possible to get a recessive blue bird but not a strong probabiity.

HiJust wondering if their are equasions like these for other mutation parings? Example: Dominant pied to normal, spangle to dilute etc.. Any equasions you have could you please share them.Thanks very muchEdit:Ive just found a table in the faq and Im wondering if I am right in understanding it.For a spangle to spangle paring, Would this table be correct:Single Factor X Single Factor = 25% Double Factor= 50% Single Factor= 25% NormalFor spangle to a normal pairing, would this table be correct:Single Factor X Normal = 50% Single Factor= 50% NormalFor rec pied to rec pied, would this table be correct:Recessive X Recessive = 100% Recessivefor light green split blue to light green split blue, would this table be correct?Normal/Recessive X Normal/Recessive = 25% Normal= 50% Normal/Recessive= 25% RecessiveNB: Visually you will be unable to tell which normals are also split recessiveif these are correct then I am well on my way to mastering genetics.

Yes! Note that the dominant/recessive thing happening with the greens and blues works in the same way. Light green/blue x light green/blue = 25% light green 50% light green split blue and 25% blue.Out of your pairing above it will be possible to get a recessive blue bird but not a strong probabiity.

The other examples you mentioned work the same way. Sex-linked inheritance is a new chapter. Violets are tricky too. Crests - well, I'm still learning! There are a few other strange ones out there too.

There is a topic pinned on the violet factor.

 

You seem to be geting your head around the dark factors so have a go at the violet factor.

It is a bit diferent as the violet factor can be attached to either the light factor or dark factor in a violet cobalt (Visual Violet)

 

I like to symbolise light factors as LL, 1 x Dark Factor as LD, as 2 x Dark Factors as DD

So a Skyblue is LL

A cobalt is LD

a Mauve is DD

 

It helps when you go into Violets eg a Violet Cobalt can be writen as LvD or LDv

 

UNDERSTANDING THE VIOLET FACTOR

Edited January 3, 200916 yr by Daz

Thankyou very much Jaz, elly and Daz.

 

Im going to try violets now, Ill let you know how I go.

 

EDit: With these tables, I can tell what a spangle paired to a normal's babies will be, a spangle paired to a spangles babie's will be, but I cannot tell what a spangle paired to another mutations babys will be.

For example:

Spangle paired to recessive pied:

I am just guessing it would be all spangles split recessive pieds unless the spangle is split pied. Can I use these tables to get this information?

 

Nevermind I scrolled down and found the dominant to recessive table

Edited January 4, 200916 yr by pearce

Nevermind I scrolled down and found the dominant to recessive table

 

Which thread are you looking at? I can't find it... Don't worry found it

 

http://forums.budgiebreeders.asn.au/faqs/i...eeding%20tables

Edited January 4, 200916 yr by JimmyBanks

It has all the sex linked tables aswell so its very good.

yeah it is but it doesn't have percentages besides the sex linked... I'm guessing that its either 25 or 50

yeah it is but it doesn't have percentages besides the sex linked... I'm guessing that its either 25 or 50

 

 

Yes your right, Oh well im not up to sex linked yet anyway.