Posted April 25, 200718 yr I was just wondering, how you calculate the percentage of the outcomes if you have a pair of budgies. Ive seen it been done a few times... You probably need to now what mutations are dominant to what right? Is there any list or something? I know how to sex a budgie and i can mostly figure out what mutation it is, but how do i calculate what the babies mutation are going to be like?? Edited April 25, 200718 yr by Marlony
April 25, 200718 yr The percentages of out comes are worked out over 100s of chicks. So don't think you'l get the outcome in one clutch. eg Spangle to normal should give 50% normal and 50% spangle. Some breeders find that they get a lot more normals and some find they get a lot more spangles.
April 25, 200718 yr As Daz says it is just a % example Tim and I both have brown eyes and it is only 25% chance that our kids would have blue eyes, guess what they both have blue eyes. We can do %;s but nature does the rest . There is a program that some people use and there are good sites out there that give you information on mutations as well as books. Here is a site I use to help figure out domancy, recessiveness etc... http://www.budgieplace.com/colors.html
April 26, 200718 yr I was just wondering, how you calculate the percentage of the outcomes if you have a pair of budgies. Ive seen it been done a few times...You probably need to now what mutations are dominant to what right? Is there any list or something? I know how to sex a budgie and i can mostly figure out what mutation it is, but how do i calculate what the babies mutation are going to be like?? This is the Basic Guide to Mating Expectations: Dominant Mating Table Dominant Varieties: Normal Green, Yellowface, Spangle, Dominant Pied, Grey, Clearflight, Violet. Single Factor X Normal = 50% Single Factor = 50% Normal Single Factor X Single Factor = 25% Double Factor = 50% Single Factor = 25% Normal Double Factor X Normal = 100% Single Factor Double Factor X Single Factor = 50% Single Factor = 50% Double Factor Double Factor X Double Factor 100% Double Factor Recesssive Mating Table Recessive Varieties: Recessive Pied, Greywing, Clearwing, Fallow, Cinnamonwing, Dilutes, Black Eyed Self, Dark Eyed Clear, Saddleback. Recessive X Recessive = 100% Recessive Normal/Recessive X Normal/Recessive = 25% Normal = 50% Normal/Recessive = 25% Recessive NB: Visually you will be unable to tell which normals are also split recessive Recessive X Normal/Recessive = 50% Recessive = 50% Normal/Recessive Normal/Recessive X Normal = 50% Normal = 50% Normal/Recessive NB: Visually you will be unable to tell which normals are also split recessive Normal X Recessive = 100% Normal/Recessive Dominant to Recessive Mating Table ie. base colour yellow(green series budgies) is dominant over base colour white (blue series budgies) Dominant X Dominant = 100% Dominant Dominant X Dominant/Recessive = 50% Dominant/Recessive = 50% Dominant NB: Visually you will be unable to tell which dominants are also split recessive Dominant X Recessive = 100% Dominant/Recessive Dominant/Recessive X Dominant/Recessive = 25% Dominant = 50% Dominant/Recessive = 25% Recessive NB: Visually you will be unable to tell which dominants are also split recessive Dominant/Recessive X Recessive = 50% Dominant/Recessive = 50% Recessive Recessive X Recessive = 100% Recessive Sex Linked Mating Table Sex Linked Varieties: Albino, Lutino, Opaline, Cinnamonwing, Lacewing, Clearbody, Slate. SL Cock X SL Hen = SL Cocks = SL Hens SL Cock X Normal Hen = Normal/SL Cocks = SL Hens Normal Cock X SL Hen = Normal/SL Cocks = Normal Hens Normal/SL Cocks X Normal Hen = Normal Cocks = Normal/SL Cocks = SL Hens = Normal Hens NB: Visually you will not be able to tell which normals are also split for the SL gene Normal/SL Cocks X SL Hen = SL Cocks = Normal/SL Cocks = SL Hens = Normal Hens [phew] Feathers. Elly:Can you please paste this into a FAQ please:D
April 26, 200718 yr Thanks Ellulah, It took a while. It will be uploaded into our FAQ section in the next 24 hours. Feathers.
April 26, 200718 yr I will can you do me a favor and any abbrevations if there are make a key and also explain that a female is xy and male is xx (opposite of human genetics). Also explaining why the female can not mask any sex linked genes because of the xy and the male can. I will let you know when I post the above and then we can add the rest. Excellent work.
April 27, 200718 yr Yes becuase you need TWO gene to make a recessive gene show (making them all DF) If they only gene one gene then they are only split for the gene.
May 4, 200718 yr Author is it same for sex-linked, you need two genes to make it visual, one for a split? Edited May 4, 200718 yr by Marlony
May 4, 200718 yr You need two gene for the males to show the sex-linked gene but only one for hens to show it. Hens can not carry sex linked genes. A hen can not give a sex linked gene to her daughter only her sons.
May 11, 200718 yr A normal a bird that is a typical green or blue budgie there is no "fancy" mutations invovled.
May 11, 200718 yr Author but if ypu breed it with a green the result would be diffrent from breeding with a ablue since green is dominant and blue is not
May 11, 200718 yr If you breed 2 green normals and they were both split for blue you would have a 25% chance of getting a blue. If you breed 1 green not split and 1 green split to blue you will get all green babies and 50% of the green babies would be split for blue. If you breed 2 green birds not split for blue you will always have green babies that are also not split to blue Is that what you are looking for? Sometimes the normal gene is dominant over another gene and other times it is recessive it depends what gene it is being paired up against.
May 11, 200718 yr Author so what is the case in feathers ""awesome" breeding expectations table??? Thanks again feathers, it really helped a lot!!!
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